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144=x(x+2)
We move all terms to the left:
144-(x(x+2))=0
We calculate terms in parentheses: -(x(x+2)), so:We get rid of parentheses
x(x+2)
We multiply parentheses
x^2+2x
Back to the equation:
-(x^2+2x)
-x^2-2x+144=0
We add all the numbers together, and all the variables
-1x^2-2x+144=0
a = -1; b = -2; c = +144;
Δ = b2-4ac
Δ = -22-4·(-1)·144
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{145}}{2*-1}=\frac{2-2\sqrt{145}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{145}}{2*-1}=\frac{2+2\sqrt{145}}{-2} $
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