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144x^2+252x-90=0
a = 144; b = 252; c = -90;
Δ = b2-4ac
Δ = 2522-4·144·(-90)
Δ = 115344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{115344}=\sqrt{1296*89}=\sqrt{1296}*\sqrt{89}=36\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-36\sqrt{89}}{2*144}=\frac{-252-36\sqrt{89}}{288} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+36\sqrt{89}}{2*144}=\frac{-252+36\sqrt{89}}{288} $
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