145=(2x+60)+(x-20)+x

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Solution for 145=(2x+60)+(x-20)+x equation: 



145=(2x+60)+(x-20)+x

We move all terms to the left:

145-((2x+60)+(x-20)+x)=0



We calculate terms in parentheses: -((2x+60)+(x-20)+x), so:

(2x+60)+(x-20)+x

We add all the numbers together, and all the variables

x+(2x+60)+(x-20)

We get rid of parentheses

x+2x+x+60-20

We add all the numbers together, and all the variables

4x+40

Back to the equation:

-(4x+40)



We get rid of parentheses

-4x-40+145=0

We add all the numbers together, and all the variables

-4x+105=0

We move all terms containing x to the left, all other terms to the right

-4x=-105

x=-105/-4

x=26+1/4

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