145=(x+2)x

Solution for 145=(x+2)x equation:

145=(x+2)x

We move all terms to the left:

145-((x+2)x)=0


We calculate terms in parentheses: -((x+2)x), so:

(x+2)x

We multiply parentheses

x^2+2x

Back to the equation:

-(x^2+2x)


We get rid of parentheses

-x^2-2x+145=0

We add all the numbers together, and all the variables

-1x^2-2x+145=0

a = -1; b = -2; c = +145;
Δ = b2-4ac
Δ = -22-4·(-1)·145
Δ = 584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{584}=\sqrt{4*146}=\sqrt{4}*\sqrt{146}=2\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{146}}{2*-1}=\frac{2-2\sqrt{146}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{146}}{2*-1}=\frac{2+2\sqrt{146}}{-2}
$