147-13(7-2t)=39-6(t-35)

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Solution for 147-13(7-2t)=39-6(t-35) equation: 



147-13(7-2t)=39-6(t-35)

We move all terms to the left:

147-13(7-2t)-(39-6(t-35))=0

We add all the numbers together, and all the variables

-13(-2t+7)-(39-6(t-35))+147=0

We multiply parentheses

26t-(39-6(t-35))-91+147=0



We calculate terms in parentheses: -(39-6(t-35)), so:

39-6(t-35)

determiningTheFunctionDomain
-6(t-35)+39

We multiply parentheses

-6t+210+39

We add all the numbers together, and all the variables

-6t+249

Back to the equation:

-(-6t+249)



We add all the numbers together, and all the variables

26t-(-6t+249)+56=0

We get rid of parentheses

26t+6t-249+56=0

We add all the numbers together, and all the variables

32t-193=0

We move all terms containing t to the left, all other terms to the right

32t=193

t=193/32

t=6+1/32

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