147=(202+206x)/(3+x)

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Solution for 147=(202+206x)/(3+x) equation:


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

147 = (206*x+202)/(x+3) // - (206*x+202)/(x+3)

147-((206*x+202)/(x+3)) = 0

(-1*(206*x+202))/(x+3)+147 = 0

(-1*(206*x+202))/(x+3)+(147*(x+3))/(x+3) = 0

147*(x+3)-1*(206*x+202) = 0

239-59*x = 0

(239-59*x)/(x+3) = 0

(239-59*x)/(x+3) = 0 // * x+3

239-59*x = 0

239-59*x = 0 // - 239

-59*x = -239 // : -59

x = -239/(-59)

x = 239/59

x = 239/59

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