147=7(4r+5)

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Solution for 147=7(4r+5) equation: 



147=7(4r+5)

We move all terms to the left:

147-(7(4r+5))=0



We calculate terms in parentheses: -(7(4r+5)), so:

7(4r+5)

We multiply parentheses

28r+35

Back to the equation:

-(28r+35)



We get rid of parentheses

-28r-35+147=0

We add all the numbers together, and all the variables

-28r+112=0

We move all terms containing r to the left, all other terms to the right

-28r=-112

r=-112/-28

r=+4

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