148-(4s-5)-s=2(s+3)

Solution for 148-(4s-5)-s=2(s+3) equation:

148-(4s-5)-s=2(s+3)

We move all terms to the left:

148-(4s-5)-s-(2(s+3))=0

We add all the numbers together, and all the variables

-1s-(4s-5)-(2(s+3))+148=0

We get rid of parentheses

-1s-4s-(2(s+3))+5+148=0


We calculate terms in parentheses: -(2(s+3)), so:

2(s+3)

We multiply parentheses

2s+6

Back to the equation:

-(2s+6)


We add all the numbers together, and all the variables

-5s-(2s+6)+153=0

We get rid of parentheses

-5s-2s-6+153=0

We add all the numbers together, and all the variables

-7s+147=0

We move all terms containing s to the left, all other terms to the right

-7s=-147

s=-147/-7

s=+21