1496=(3x+2)(x)

Solution for 1496=(3x+2)(x) equation:

1496=(3x+2)(x)

We move all terms to the left:

1496-((3x+2)(x))=0


We calculate terms in parentheses: -((3x+2)x), so:

(3x+2)x

We multiply parentheses

3x^2+2x

Back to the equation:

-(3x^2+2x)


We get rid of parentheses

-3x^2-2x+1496=0

a = -3; b = -2; c = +1496;
Δ = b2-4ac
Δ = -22-4·(-3)·1496
Δ = 17956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17956}=134$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-134}{2*-3}=\frac{-132}{-6}
=+22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+134}{2*-3}=\frac{136}{-6}
=-22+2/3
$