14=(2/3)(9x-15)

Solution for 14=(2/3)(9x-15) equation:

14=(2/3)(9x-15)

We move all terms to the left:

14-((2/3)(9x-15))=0


Domain of the equation: 3)(9x-15))!=0

x∈R


We add all the numbers together, and all the variables

-((+2/3)(9x-15))+14=0

We multiply parentheses ..

-((+18x^2+2/3*-15))+14=0

We multiply all the terms by the denominator


-((+18x^2+2+14*3*-15))=0


We calculate terms in parentheses: -((+18x^2+2+14*3*-15)), so:

(+18x^2+2+14*3*-15)

We get rid of parentheses

18x^2+2-15+14*3*

We add all the numbers together, and all the variables

18x^2

Back to the equation:

-(18x^2)


a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-36}=0$