14=(3/5)(7x+10)

Solution for 14=(3/5)(7x+10) equation:

14=(3/5)(7x+10)

We move all terms to the left:

14-((3/5)(7x+10))=0


Domain of the equation: 5)(7x+10))!=0

x∈R


We add all the numbers together, and all the variables

-((+3/5)(7x+10))+14=0

We multiply parentheses ..

-((+21x^2+3/5*10))+14=0

We multiply all the terms by the denominator


-((+21x^2+3+14*5*10))=0


We calculate terms in parentheses: -((+21x^2+3+14*5*10)), so:

(+21x^2+3+14*5*10)

We get rid of parentheses

21x^2+3+14*5*10

We add all the numbers together, and all the variables

21x^2+703

Back to the equation:

-(21x^2+703)


We get rid of parentheses

-21x^2-703=0

a = -21; b = 0; c = -703;
Δ = b2-4ac
Δ = 02-4·(-21)·(-703)
Δ = -59052
Delta is less than zero, so there is no solution for the equation