14=-10(1-3x)-28x

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Solution for 14=-10(1-3x)-28x equation: 



14=-10(1-3x)-28x

We move all terms to the left:

14-(-10(1-3x)-28x)=0

We add all the numbers together, and all the variables

-(-10(-3x+1)-28x)+14=0



We calculate terms in parentheses: -(-10(-3x+1)-28x), so:

-10(-3x+1)-28x

We add all the numbers together, and all the variables

-28x-10(-3x+1)

We multiply parentheses

-28x+30x-10

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

-2x+10+14=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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