14=2(3y+1)

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Solution for 14=2(3y+1) equation: 



14=2(3y+1)

We move all terms to the left:

14-(2(3y+1))=0



We calculate terms in parentheses: -(2(3y+1)), so:

2(3y+1)

We multiply parentheses

6y+2

Back to the equation:

-(6y+2)



We get rid of parentheses

-6y-2+14=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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