14=3(d+1)+-1

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Solution for 14=3(d+1)+-1 equation: 



14=3(d+1)+-1

We move all terms to the left:

14-(3(d+1)+-1)=0

We use the square of the difference formula

-(3(d+1)-1)+14=0



We calculate terms in parentheses: -(3(d+1)-1), so:

3(d+1)-1

We multiply parentheses

3d+3-1

We add all the numbers together, and all the variables

3d+2

Back to the equation:

-(3d+2)



We get rid of parentheses

-3d-2+14=0

We add all the numbers together, and all the variables

-3d+12=0

We move all terms containing d to the left, all other terms to the right

-3d=-12

d=-12/-3

d=+4

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