14=3(y+2)-(y-4)

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Solution for 14=3(y+2)-(y-4) equation:


Simplifying
14 = 3(y + 2) + -1(y + -4)

Reorder the terms:
14 = 3(2 + y) + -1(y + -4)
14 = (2 * 3 + y * 3) + -1(y + -4)
14 = (6 + 3y) + -1(y + -4)

Reorder the terms:
14 = 6 + 3y + -1(-4 + y)
14 = 6 + 3y + (-4 * -1 + y * -1)
14 = 6 + 3y + (4 + -1y)

Reorder the terms:
14 = 6 + 4 + 3y + -1y

Combine like terms: 6 + 4 = 10
14 = 10 + 3y + -1y

Combine like terms: 3y + -1y = 2y
14 = 10 + 2y

Solving
14 = 10 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
14 + -2y = 10 + 2y + -2y

Combine like terms: 2y + -2y = 0
14 + -2y = 10 + 0
14 + -2y = 10

Add '-14' to each side of the equation.
14 + -14 + -2y = 10 + -14

Combine like terms: 14 + -14 = 0
0 + -2y = 10 + -14
-2y = 10 + -14

Combine like terms: 10 + -14 = -4
-2y = -4

Divide each side by '-2'.
y = 2

Simplifying
y = 2

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