14=n(n-3)/2

Solution for 14=n(n-3)/2 equation:

14=n(n-3)/2

We move all terms to the left:

14-(n(n-3)/2)=0

We multiply all the terms by the denominator


-(n(n-3)+14*2)=0


We calculate terms in parentheses: -(n(n-3)+14*2), so:

n(n-3)+14*2

We add all the numbers together, and all the variables

n(n-3)+28

We multiply parentheses

n^2-3n+28

Back to the equation:

-(n^2-3n+28)


We get rid of parentheses

-n^2+3n-28=0

We add all the numbers together, and all the variables

-1n^2+3n-28=0

a = -1; b = 3; c = -28;
Δ = b2-4ac
Δ = 32-4·(-1)·(-28)
Δ = -103
Delta is less than zero, so there is no solution for the equation