14=z2

Solution for 14=z2 equation:

14=z2

We move all terms to the left:

14-(z2)=0

We add all the numbers together, and all the variables

-1z^2+14=0

a = -1; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·(-1)·14
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{14}}{2*-1}=\frac{0-2\sqrt{14}}{-2}
=-\frac{2\sqrt{14}}{-2}
=-\frac{\sqrt{14}}{-1}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{14}}{2*-1}=\frac{0+2\sqrt{14}}{-2}
=\frac{2\sqrt{14}}{-2}
=\frac{\sqrt{14}}{-1}
$