14a-(3a-2)=(5a+2-(a-1))

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Solution for 14a-(3a-2)=(5a+2-(a-1)) equation: 



14a-(3a-2)=(5a+2-(a-1))

We move all terms to the left:

14a-(3a-2)-((5a+2-(a-1)))=0

We get rid of parentheses

14a-3a-((5a+2-(a-1)))+2=0



We calculate terms in parentheses: -((5a+2-(a-1))), so:

(5a+2-(a-1))



We calculate terms in parentheses: +(5a+2-(a-1)), so:

5a+2-(a-1)

determiningTheFunctionDomain
5a-(a-1)+2

We get rid of parentheses

5a-a+1+2

We add all the numbers together, and all the variables

4a+3

Back to the equation:

+(4a+3)



We get rid of parentheses

4a+3

Back to the equation:

-(4a+3)



We add all the numbers together, and all the variables

11a-(4a+3)+2=0

We get rid of parentheses

11a-4a-3+2=0

We add all the numbers together, and all the variables

7a-1=0

We move all terms containing a to the left, all other terms to the right

7a=1

a=1/7

a=1/7

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