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14b^2=16
We move all terms to the left:
14b^2-(16)=0
a = 14; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·14·(-16)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{14}}{2*14}=\frac{0-8\sqrt{14}}{28} =-\frac{8\sqrt{14}}{28} =-\frac{2\sqrt{14}}{7} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{14}}{2*14}=\frac{0+8\sqrt{14}}{28} =\frac{8\sqrt{14}}{28} =\frac{2\sqrt{14}}{7} $
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