14f+49=-f2

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Solution for 14f+49=-f2 equation: 



14f+49=-f2

We move all terms to the left:

14f+49-(-f2)=0

We add all the numbers together, and all the variables

-(-1f^2)+14f+49=0

We get rid of parentheses

1f^2+14f+49=0

We add all the numbers together, and all the variables

f^2+14f+49=0

a = 1; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·1·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{-14}{2}=-7$

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