14j-3(8j-4)=2(4j+1)-3(8j-4)

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Solution for 14j-3(8j-4)=2(4j+1)-3(8j-4) equation: 



14j-3(8j-4)=2(4j+1)-3(8j-4)

We move all terms to the left:

14j-3(8j-4)-(2(4j+1)-3(8j-4))=0

We multiply parentheses

14j-24j-(2(4j+1)-3(8j-4))+12=0



We calculate terms in parentheses: -(2(4j+1)-3(8j-4)), so:

2(4j+1)-3(8j-4)

We multiply parentheses

8j-24j+2+12

We add all the numbers together, and all the variables

-16j+14

Back to the equation:

-(-16j+14)



We add all the numbers together, and all the variables

-10j-(-16j+14)+12=0

We get rid of parentheses

-10j+16j-14+12=0

We add all the numbers together, and all the variables

6j-2=0

We move all terms containing j to the left, all other terms to the right

6j=2

j=2/6

j=1/3

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