14t-6(2t+4)=8(t-3)-6t

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Solution for 14t-6(2t+4)=8(t-3)-6t equation: 



14t-6(2t+4)=8(t-3)-6t

We move all terms to the left:

14t-6(2t+4)-(8(t-3)-6t)=0

We multiply parentheses

14t-12t-(8(t-3)-6t)-24=0



We calculate terms in parentheses: -(8(t-3)-6t), so:

8(t-3)-6t

We add all the numbers together, and all the variables

-6t+8(t-3)

We multiply parentheses

-6t+8t-24

We add all the numbers together, and all the variables

2t-24

Back to the equation:

-(2t-24)



We add all the numbers together, and all the variables

2t-(2t-24)-24=0

We get rid of parentheses

2t-2t+24-24=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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