14u+27=2u+3(9+4u)

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Solution for 14u+27=2u+3(9+4u) equation: 



14u+27=2u+3(9+4u)

We move all terms to the left:

14u+27-(2u+3(9+4u))=0

We add all the numbers together, and all the variables

14u-(2u+3(4u+9))+27=0



We calculate terms in parentheses: -(2u+3(4u+9)), so:

2u+3(4u+9)

We multiply parentheses

2u+12u+27

We add all the numbers together, and all the variables

14u+27

Back to the equation:

-(14u+27)



We get rid of parentheses

14u-14u-27+27=0

We add all the numbers together, and all the variables

=0

u=0/1

u=0

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