14u+27=2u+3(9+4u)

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Solution for 14u+27=2u+3(9+4u) equation:



14u+27=2u+3(9+4u)
We move all terms to the left:
14u+27-(2u+3(9+4u))=0
We add all the numbers together, and all the variables
14u-(2u+3(4u+9))+27=0
We calculate terms in parentheses: -(2u+3(4u+9)), so:
2u+3(4u+9)
We multiply parentheses
2u+12u+27
We add all the numbers together, and all the variables
14u+27
Back to the equation:
-(14u+27)
We get rid of parentheses
14u-14u-27+27=0
We add all the numbers together, and all the variables
=0
u=0/1
u=0

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