14u2+23u+3=0

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Solution for 14u2+23u+3=0 equation: 



14u^2+23u+3=0

a = 14; b = 23; c = +3;
Δ = b2-4ac
Δ = 232-4·14·3
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$


$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-19}{2*14}=\frac{-42}{28}
=-1+1/2
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+19}{2*14}=\frac{-4}{28}
=-1/7
$

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