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14v^2+51v+7=0
a = 14; b = 51; c = +7;
Δ = b2-4ac
Δ = 512-4·14·7
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-47}{2*14}=\frac{-98}{28} =-3+1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+47}{2*14}=\frac{-4}{28} =-1/7 $
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