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14v^2-23v+8=0
a = 14; b = -23; c = +8;
Δ = b2-4ac
Δ = -232-4·14·8
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-9}{2*14}=\frac{14}{28} =1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+9}{2*14}=\frac{32}{28} =1+1/7 $
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