14x(16x-3)=17

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Solution for 14x(16x-3)=17 equation:



14x(16x-3)=17
We move all terms to the left:
14x(16x-3)-(17)=0
We multiply parentheses
224x^2-42x-17=0
a = 224; b = -42; c = -17;
Δ = b2-4ac
Δ = -422-4·224·(-17)
Δ = 16996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{16996}=\sqrt{4*4249}=\sqrt{4}*\sqrt{4249}=2\sqrt{4249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{4249}}{2*224}=\frac{42-2\sqrt{4249}}{448} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{4249}}{2*224}=\frac{42+2\sqrt{4249}}{448} $

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