14x-(3x+2)=11-(x-5)+18

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Solution for 14x-(3x+2)=11-(x-5)+18 equation:



14x-(3x+2)=11-(x-5)+18
We move all terms to the left:
14x-(3x+2)-(11-(x-5)+18)=0
We get rid of parentheses
14x-3x-(11-(x-5)+18)-2=0
We calculate terms in parentheses: -(11-(x-5)+18), so:
11-(x-5)+18
determiningTheFunctionDomain -(x-5)+11+18
We add all the numbers together, and all the variables
-(x-5)+29
We get rid of parentheses
-x+5+29
We add all the numbers together, and all the variables
-1x+34
Back to the equation:
-(-1x+34)
We add all the numbers together, and all the variables
11x-(-1x+34)-2=0
We get rid of parentheses
11x+1x-34-2=0
We add all the numbers together, and all the variables
12x-36=0
We move all terms containing x to the left, all other terms to the right
12x=36
x=36/12
x=3

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