14x-(3x+2)=11-(x-5)+18

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Solution for 14x-(3x+2)=11-(x-5)+18 equation: 



14x-(3x+2)=11-(x-5)+18

We move all terms to the left:

14x-(3x+2)-(11-(x-5)+18)=0

We get rid of parentheses

14x-3x-(11-(x-5)+18)-2=0



We calculate terms in parentheses: -(11-(x-5)+18), so:

11-(x-5)+18

determiningTheFunctionDomain
-(x-5)+11+18

We add all the numbers together, and all the variables

-(x-5)+29

We get rid of parentheses

-x+5+29

We add all the numbers together, and all the variables

-1x+34

Back to the equation:

-(-1x+34)



We add all the numbers together, and all the variables

11x-(-1x+34)-2=0

We get rid of parentheses

11x+1x-34-2=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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