14x-1/2(4x+6)=3(x-4)-18

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Solution for 14x-1/2(4x+6)=3(x-4)-18 equation: 



14x-1/2(4x+6)=3(x-4)-18

We move all terms to the left:

14x-1/2(4x+6)-(3(x-4)-18)=0



Domain of the equation: 2(4x+6)!=0

x∈R



We multiply all the terms by the denominator


14x*2(4x+6)-((3(x-4)-18))*2(4x+6)-1=0



We calculate terms in parentheses: -((3(x-4)-18))*2(4x+6), so:

(3(x-4)-18))*2(4x+6



Wy multiply elements

28x^2(4-((3(x-4)-18))*2(4x+6)-1=0

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