14x-13=1/3x+1

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Solution for 14x-13=1/3x+1 equation:



14x-13=1/3x+1
We move all terms to the left:
14x-13-(1/3x+1)=0
Domain of the equation: 3x+1)!=0
x∈R
We get rid of parentheses
14x-1/3x-1-13=0
We multiply all the terms by the denominator
14x*3x-1*3x-13*3x-1=0
Wy multiply elements
42x^2-3x-39x-1=0
We add all the numbers together, and all the variables
42x^2-42x-1=0
a = 42; b = -42; c = -1;
Δ = b2-4ac
Δ = -422-4·42·(-1)
Δ = 1932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1932}=\sqrt{4*483}=\sqrt{4}*\sqrt{483}=2\sqrt{483}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{483}}{2*42}=\frac{42-2\sqrt{483}}{84} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{483}}{2*42}=\frac{42+2\sqrt{483}}{84} $

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