14x-4(x-2)=5(2x+1)+3

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Solution for 14x-4(x-2)=5(2x+1)+3 equation: 


Simplifying
14x + -4(x + -2) = 5(2x + 1) + 3

Reorder the terms:
14x + -4(-2 + x) = 5(2x + 1) + 3
14x + (-2 * -4 + x * -4) = 5(2x + 1) + 3
14x + (8 + -4x) = 5(2x + 1) + 3

Reorder the terms:
8 + 14x + -4x = 5(2x + 1) + 3

Combine like terms: 14x + -4x = 10x
8 + 10x = 5(2x + 1) + 3

Reorder the terms:
8 + 10x = 5(1 + 2x) + 3
8 + 10x = (1 * 5 + 2x * 5) + 3
8 + 10x = (5 + 10x) + 3

Reorder the terms:
8 + 10x = 5 + 3 + 10x

Combine like terms: 5 + 3 = 8
8 + 10x = 8 + 10x

Add '-8' to each side of the equation.
8 + -8 + 10x = 8 + -8 + 10x

Combine like terms: 8 + -8 = 0
0 + 10x = 8 + -8 + 10x
10x = 8 + -8 + 10x

Combine like terms: 8 + -8 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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