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14x-4=5x(x+2)
We move all terms to the left:
14x-4-(5x(x+2))=0
We calculate terms in parentheses: -(5x(x+2)), so:We get rid of parentheses
5x(x+2)
We multiply parentheses
5x^2+10x
Back to the equation:
-(5x^2+10x)
-5x^2+14x-10x-4=0
We add all the numbers together, and all the variables
-5x^2+4x-4=0
a = -5; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-5)·(-4)
Δ = -64
Delta is less than zero, so there is no solution for the equation
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