14x2+10=150;5

Solution for 14x2+10=150;5 equation:

14x^2+10=1505

We move all terms to the left:

14x^2+10-(1505)=0

We add all the numbers together, and all the variables

14x^2-1495=0

a = 14; b = 0; c = -1495;
Δ = b2-4ac
Δ = 02-4·14·(-1495)
Δ = 83720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{83720}=\sqrt{4*20930}=\sqrt{4}*\sqrt{20930}=2\sqrt{20930}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{20930}}{2*14}=\frac{0-2\sqrt{20930}}{28}
=-\frac{2\sqrt{20930}}{28}
=-\frac{\sqrt{20930}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{20930}}{2*14}=\frac{0+2\sqrt{20930}}{28}
=\frac{2\sqrt{20930}}{28}
=\frac{\sqrt{20930}}{14}
$