14x2+12=-29x

Solution for 14x2+12=-29x equation:

14x^2+12=-29x

We move all terms to the left:

14x^2+12-(-29x)=0

We get rid of parentheses

14x^2+29x+12=0

a = 14; b = 29; c = +12;
Δ = b2-4ac
Δ = 292-4·14·12
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-13}{2*14}=\frac{-42}{28}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+13}{2*14}=\frac{-16}{28}
=-4/7
$