14x2+14x-17=0

Solution for 14x2+14x-17=0 equation:

14x^2+14x-17=0

a = 14; b = 14; c = -17;
Δ = b2-4ac
Δ = 142-4·14·(-17)
Δ = 1148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1148}=\sqrt{4*287}=\sqrt{4}*\sqrt{287}=2\sqrt{287}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{287}}{2*14}=\frac{-14-2\sqrt{287}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{287}}{2*14}=\frac{-14+2\sqrt{287}}{28}
$