14x2+14x-7=0

Solution for 14x2+14x-7=0 equation:

14x^2+14x-7=0

a = 14; b = 14; c = -7;
Δ = b2-4ac
Δ = 142-4·14·(-7)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{3}}{2*14}=\frac{-14-14\sqrt{3}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{3}}{2*14}=\frac{-14+14\sqrt{3}}{28}
$