14x2+20x-18=0

Solution for 14x2+20x-18=0 equation:

14x^2+20x-18=0

a = 14; b = 20; c = -18;
Δ = b2-4ac
Δ = 202-4·14·(-18)
Δ = 1408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1408}=\sqrt{64*22}=\sqrt{64}*\sqrt{22}=8\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8\sqrt{22}}{2*14}=\frac{-20-8\sqrt{22}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8\sqrt{22}}{2*14}=\frac{-20+8\sqrt{22}}{28}
$