14x2+45x+25=0

Solution for 14x2+45x+25=0 equation:

14x^2+45x+25=0

a = 14; b = 45; c = +25;
Δ = b2-4ac
Δ = 452-4·14·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-25}{2*14}=\frac{-70}{28}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+25}{2*14}=\frac{-20}{28}
=-5/7
$