14x2+x=4

Solution for 14x2+x=4 equation:

14x^2+x=4

We move all terms to the left:

14x^2+x-(4)=0

a = 14; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·14·(-4)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*14}=\frac{-16}{28}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*14}=\frac{14}{28}
=1/2
$