14x2-16x-5=0

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Solution for 14x2-16x-5=0 equation:



14x^2-16x-5=0
a = 14; b = -16; c = -5;
Δ = b2-4ac
Δ = -162-4·14·(-5)
Δ = 536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{536}=\sqrt{4*134}=\sqrt{4}*\sqrt{134}=2\sqrt{134}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{134}}{2*14}=\frac{16-2\sqrt{134}}{28} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{134}}{2*14}=\frac{16+2\sqrt{134}}{28} $

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