14x2-19x=3

Solution for 14x2-19x=3 equation:

14x^2-19x=3

We move all terms to the left:

14x^2-19x-(3)=0

a = 14; b = -19; c = -3;
Δ = b2-4ac
Δ = -192-4·14·(-3)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-23}{2*14}=\frac{-4}{28}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+23}{2*14}=\frac{42}{28}
=1+1/2
$