14x2=4x+8

Solution for 14x2=4x+8 equation:

14x^2=4x+8

We move all terms to the left:

14x^2-(4x+8)=0

We get rid of parentheses

14x^2-4x-8=0

a = 14; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·14·(-8)
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{29}}{2*14}=\frac{4-4\sqrt{29}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{29}}{2*14}=\frac{4+4\sqrt{29}}{28}
$