14x=x2+45

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Solution for 14x=x2+45 equation:



14x=x2+45
We move all terms to the left:
14x-(x2+45)=0
We add all the numbers together, and all the variables
-(+x^2+45)+14x=0
We get rid of parentheses
-x^2+14x-45=0
We add all the numbers together, and all the variables
-1x^2+14x-45=0
a = -1; b = 14; c = -45;
Δ = b2-4ac
Δ = 142-4·(-1)·(-45)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*-1}=\frac{-18}{-2} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*-1}=\frac{-10}{-2} =+5 $

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