14y+2(y-3)=10y+30

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Solution for 14y+2(y-3)=10y+30 equation:



14y+2(y-3)=10y+30
We move all terms to the left:
14y+2(y-3)-(10y+30)=0
We multiply parentheses
14y+2y-(10y+30)-6=0
We get rid of parentheses
14y+2y-10y-30-6=0
We add all the numbers together, and all the variables
6y-36=0
We move all terms containing y to the left, all other terms to the right
6y=36
y=36/6
y=6

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