14y+2(y-3)=10y+30

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Solution for 14y+2(y-3)=10y+30 equation: 



14y+2(y-3)=10y+30

We move all terms to the left:

14y+2(y-3)-(10y+30)=0

We multiply parentheses

14y+2y-(10y+30)-6=0

We get rid of parentheses

14y+2y-10y-30-6=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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