14y+6-8y=4(y-3)

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Solution for 14y+6-8y=4(y-3) equation: 



14y+6-8y=4(y-3)

We move all terms to the left:

14y+6-8y-(4(y-3))=0

We add all the numbers together, and all the variables

6y-(4(y-3))+6=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We get rid of parentheses

6y-4y+12+6=0

We add all the numbers together, and all the variables

2y+18=0

We move all terms containing y to the left, all other terms to the right

2y=-18

y=-18/2

y=-9

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