If it's not what You are looking for type in the equation solver your own equation and let us solve it.
14y^2-112y=0
a = 14; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·14·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*14}=\frac{0}{28} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*14}=\frac{224}{28} =8 $
| -2(w+2)=2w-4+2(7w+4) | | -3(-7x+4)-3x=4(x-3)-4 | | -39-7x+4)-3x=4(x-3)-4 | | -4(3x-4)+2x=4(x+7) | | 6(x-7)+7x=23 | | X/2-2x=4 | | x^2-1 | | 7u+15=50 | | y^2+2^2=2^2 | | y^22^2=y^2 | | x-24+4=140 | | x*x*x*x+12*x+12=0 | | 5x+1/6=7+3x/2 | | 1=3x;4=x+30 | | x=x+(x+1) | | 2x4.5+3=3x4.5-1,5 | | 2x4.5+3=3x4.5-105 | | 3x4+2=4x5-3 | | X=7a | | 0.7x+0.05=x-0.2 | | 2x-3÷3x+2=2÷3 | | a+2a+3=-1+2a+4 | | 2x-3/3x+2=2/3 | | 4b/2+3=11+3 | | 4x(x-1)=33 | | (12/x+1)+(9/x-2)=5 | | -18=x|-2-3 | | 3z=z+20 | | (x+2)/3+(x+3)/8=5/6 | | 6x+53=-25 | | -126=-35+7x | | y+10y^-1=7 |