14z-4(z+2)=2(z-2)+3(z-8)

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Solution for 14z-4(z+2)=2(z-2)+3(z-8) equation:


14z-4(z+2)=2(z-2)+3(z-8)

We simplify the equation to the form, which is simple to understand 
14z-4(z+2)=2(z-2)+3(z-8)

Reorder the terms in parentheses
14z+(-4z-8)=2*(z-2)+3*(z-8)

Remove unnecessary parentheses
+14z-4z-8=+2+*(+z-2+)+3+*(+z-8+)

Reorder the terms in parentheses
14z-4z-8=+(+2z-4)+3*(z-8)

Remove unnecessary parentheses
+14z-4z-8=+2z-4+3+*(+z-8+)

Reorder the terms in parentheses
14z-4z-8=+2z-4+(+3z-24)

Remove unnecessary parentheses
+14z-4z-8=+2z-4+3z-24

We move all terms containing z to the left and all other terms to the right. 
+14z-4z-2z-3z=-4-24+8

We simplify left and right side of the equation. 
+5z=-20

We divide both sides of the equation by 5 to get z. 
z=-4

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