15(1/3y+3)=6(y+9)

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Solution for 15(1/3y+3)=6(y+9) equation: 



15(1/3y+3)=6(y+9)

We move all terms to the left:

15(1/3y+3)-(6(y+9))=0



Domain of the equation: 3y+3)!=0

y∈R



We multiply parentheses

15y-(6(y+9))+45=0



We calculate terms in parentheses: -(6(y+9)), so:

6(y+9)

We multiply parentheses

6y+54

Back to the equation:

-(6y+54)



We get rid of parentheses

15y-6y-54+45=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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