15(10)3f-120=10(10)+2f

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Solution for 15(10)3f-120=10(10)+2f equation: 



15(10)3f-120=10(10)+2f

We move all terms to the left:

15(10)3f-120-(10(10)+2f)=0

We add all the numbers together, and all the variables

15103f-(2f+1010)-120=0

We get rid of parentheses

15103f-2f-1010-120=0

We add all the numbers together, and all the variables

15101f-1130=0

We move all terms containing f to the left, all other terms to the right

15101f=1130

f=1130/15101

f=1130/15101

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