15(2-y)-5(y+6)/1-3y=10

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Solution for 15(2-y)-5(y+6)/1-3y=10 equation: 



15(2-y)-5(y+6)/1-3y=10

We move all terms to the left:

15(2-y)-5(y+6)/1-3y-(10)=0

We add all the numbers together, and all the variables

15(-1y+2)-5(y+6)/1-3y-10=0

We add all the numbers together, and all the variables

-3y+15(-1y+2)-5(y+6)/1-10=0

We multiply parentheses

-3y-15y-5(y+6)/1+30-10=0

We multiply all the terms by the denominator


-3y*1-15y*1-5(y+6)+30*1-10*1=0

We add all the numbers together, and all the variables

-3y*1-15y*1-5(y+6)+20=0

We multiply parentheses

-3y*1-15y*1-5y-30+20=0

Wy multiply elements

-3y-15y-5y-30+20=0

We add all the numbers together, and all the variables

-23y-10=0

We move all terms containing y to the left, all other terms to the right

-23y=10

y=10/-23

y=-10/23

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